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Author Topic: Enchanters Wardstone vs Destroy Magic and Purge Magic  (Read 2364 times)

Boocheck

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Enchanters Wardstone vs Destroy Magic and Purge Magic
« on: August 20, 2013, 01:39:35 PM »
Well, more than question, we (my gaming group) need confirmation.

If my enemy have 3 wardstones and i cast Purge magic on his FM, do i have to pay additional mana?

Sometimes it is really hard to save up 10 mana just to destory Mind Control on my Bogran Bloodstone ;)
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jacksmack

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Re: Enchanters Wardstone vs Destroy Magic and Purge Magic
« Reply #1 on: August 20, 2013, 02:30:07 PM »
Well...

Purge magic has a fixed cost - 12 mana.

1. Cast spell. Turn it face up declare target check for range and LOS and pay mana.

2. Opponent can counter the spell now with nullify if he has it on target.

3. Spell resolves. Here you pay 2 extra mana for each Wardstone the opponent has in play PER enchanment you wish to destroy.


Shad0w

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Re: Enchanters Wardstone vs Destroy Magic and Purge Magic
« Reply #2 on: August 20, 2013, 02:34:02 PM »
Well...

Purge magic has a fixed cost - 12 mana.

1. Cast spell. Turn it face up declare target check for range and LOS and pay mana.

2. Opponent can counter the spell now with nullify if he has it on target.

3. Spell resolves. Here you pay 2 extra mana for each Wardstone the opponent has in play PER enchanment you wish to destroy.

Jack is correct
"Darth come prove to meet you are worthy of the fighting for your school in the arena and not just another scholar to be discarded like an worn out rag doll"


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Boocheck

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Re: Enchanters Wardstone vs Destroy Magic and Purge Magic
« Reply #3 on: August 20, 2013, 11:54:25 PM »
So if FM have 4 enchants and 3 wardstones in play and i cast Purge magic, i will pay 12 mana and then 4*2*3 mana?

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sIKE

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Re: Enchanters Wardstone vs Destroy Magic and Purge Magic
« Reply #4 on: August 21, 2013, 12:10:54 AM »
So if FM have 4 enchants and 3 wardstones in play and i cast Purge magic, i will pay 12 mana and then 4*2*3 mana?
If you want to get rid of all four Enchantments, then yes. But if there are only two of interest then (2*2)3.
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